Integrand size = 25, antiderivative size = 131 \[ \int \frac {\sin ^3(e+f x)}{\left (a+b \tan ^2(e+f x)\right )^{3/2}} \, dx=-\frac {(3 a+b) \cos (e+f x)}{3 (a-b)^2 f \sqrt {a-b+b \sec ^2(e+f x)}}+\frac {\cos ^3(e+f x)}{3 (a-b) f \sqrt {a-b+b \sec ^2(e+f x)}}-\frac {2 b (3 a+b) \sec (e+f x)}{3 (a-b)^3 f \sqrt {a-b+b \sec ^2(e+f x)}} \]
[Out]
Time = 0.17 (sec) , antiderivative size = 131, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.160, Rules used = {3745, 464, 277, 197} \[ \int \frac {\sin ^3(e+f x)}{\left (a+b \tan ^2(e+f x)\right )^{3/2}} \, dx=-\frac {2 b (3 a+b) \sec (e+f x)}{3 f (a-b)^3 \sqrt {a+b \sec ^2(e+f x)-b}}+\frac {\cos ^3(e+f x)}{3 f (a-b) \sqrt {a+b \sec ^2(e+f x)-b}}-\frac {(3 a+b) \cos (e+f x)}{3 f (a-b)^2 \sqrt {a+b \sec ^2(e+f x)-b}} \]
[In]
[Out]
Rule 197
Rule 277
Rule 464
Rule 3745
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {-1+x^2}{x^4 \left (a-b+b x^2\right )^{3/2}} \, dx,x,\sec (e+f x)\right )}{f} \\ & = \frac {\cos ^3(e+f x)}{3 (a-b) f \sqrt {a-b+b \sec ^2(e+f x)}}+\frac {(3 a+b) \text {Subst}\left (\int \frac {1}{x^2 \left (a-b+b x^2\right )^{3/2}} \, dx,x,\sec (e+f x)\right )}{3 (a-b) f} \\ & = -\frac {(3 a+b) \cos (e+f x)}{3 (a-b)^2 f \sqrt {a-b+b \sec ^2(e+f x)}}+\frac {\cos ^3(e+f x)}{3 (a-b) f \sqrt {a-b+b \sec ^2(e+f x)}}-\frac {(2 b (3 a+b)) \text {Subst}\left (\int \frac {1}{\left (a-b+b x^2\right )^{3/2}} \, dx,x,\sec (e+f x)\right )}{3 (a-b)^2 f} \\ & = -\frac {(3 a+b) \cos (e+f x)}{3 (a-b)^2 f \sqrt {a-b+b \sec ^2(e+f x)}}+\frac {\cos ^3(e+f x)}{3 (a-b) f \sqrt {a-b+b \sec ^2(e+f x)}}-\frac {2 b (3 a+b) \sec (e+f x)}{3 (a-b)^3 f \sqrt {a-b+b \sec ^2(e+f x)}} \\ \end{align*}
Time = 5.50 (sec) , antiderivative size = 106, normalized size of antiderivative = 0.81 \[ \int \frac {\sin ^3(e+f x)}{\left (a+b \tan ^2(e+f x)\right )^{3/2}} \, dx=-\frac {\left (9 a^2+46 a b+9 b^2+8 \left (a^2-b^2\right ) \cos (2 (e+f x))-(a-b)^2 \cos (4 (e+f x))\right ) \sec (e+f x)}{12 \sqrt {2} (a-b)^3 f \sqrt {(a+b+(a-b) \cos (2 (e+f x))) \sec ^2(e+f x)}} \]
[In]
[Out]
Time = 1.12 (sec) , antiderivative size = 208, normalized size of antiderivative = 1.59
method | result | size |
default | \(-\frac {\left (a -b \right ) \left (\sin \left (f x +e \right )^{4} \cos \left (f x +e \right )^{2} b^{3}+3 \sin \left (f x +e \right )^{2} \cos \left (f x +e \right )^{4} a \,b^{2}-a^{3} \cos \left (f x +e \right )^{6}+3 a^{2} b \cos \left (f x +e \right )^{6}+2 \sin \left (f x +e \right )^{4} b^{3}+3 a^{3} \cos \left (f x +e \right )^{4}-6 a^{2} b \cos \left (f x +e \right )^{4}+6 \sin \left (f x +e \right )^{2} a \,b^{2}+9 a^{2} b \cos \left (f x +e \right )^{2}\right ) a^{4} \sec \left (f x +e \right )^{3}}{3 f \left (\sqrt {-b \left (a -b \right )}-a +b \right )^{4} \left (\sqrt {-b \left (a -b \right )}+a -b \right )^{4} \left (a +b \tan \left (f x +e \right )^{2}\right )^{\frac {3}{2}}}\) | \(208\) |
[In]
[Out]
none
Time = 0.35 (sec) , antiderivative size = 158, normalized size of antiderivative = 1.21 \[ \int \frac {\sin ^3(e+f x)}{\left (a+b \tan ^2(e+f x)\right )^{3/2}} \, dx=\frac {{\left ({\left (a^{2} - 2 \, a b + b^{2}\right )} \cos \left (f x + e\right )^{5} - {\left (3 \, a^{2} - 2 \, a b - b^{2}\right )} \cos \left (f x + e\right )^{3} - 2 \, {\left (3 \, a b + b^{2}\right )} \cos \left (f x + e\right )\right )} \sqrt {\frac {{\left (a - b\right )} \cos \left (f x + e\right )^{2} + b}{\cos \left (f x + e\right )^{2}}}}{3 \, {\left ({\left (a^{4} - 4 \, a^{3} b + 6 \, a^{2} b^{2} - 4 \, a b^{3} + b^{4}\right )} f \cos \left (f x + e\right )^{2} + {\left (a^{3} b - 3 \, a^{2} b^{2} + 3 \, a b^{3} - b^{4}\right )} f\right )}} \]
[In]
[Out]
Timed out. \[ \int \frac {\sin ^3(e+f x)}{\left (a+b \tan ^2(e+f x)\right )^{3/2}} \, dx=\text {Timed out} \]
[In]
[Out]
none
Time = 0.23 (sec) , antiderivative size = 216, normalized size of antiderivative = 1.65 \[ \int \frac {\sin ^3(e+f x)}{\left (a+b \tan ^2(e+f x)\right )^{3/2}} \, dx=-\frac {\frac {3 \, \sqrt {a - b + \frac {b}{\cos \left (f x + e\right )^{2}}} \cos \left (f x + e\right )}{a^{2} - 2 \, a b + b^{2}} - \frac {{\left (a - b + \frac {b}{\cos \left (f x + e\right )^{2}}\right )}^{\frac {3}{2}} \cos \left (f x + e\right )^{3} - 6 \, \sqrt {a - b + \frac {b}{\cos \left (f x + e\right )^{2}}} b \cos \left (f x + e\right )}{a^{3} - 3 \, a^{2} b + 3 \, a b^{2} - b^{3}} + \frac {3 \, b^{2}}{{\left (a^{3} - 3 \, a^{2} b + 3 \, a b^{2} - b^{3}\right )} \sqrt {a - b + \frac {b}{\cos \left (f x + e\right )^{2}}} \cos \left (f x + e\right )} + \frac {3 \, b}{{\left (a^{2} - 2 \, a b + b^{2}\right )} \sqrt {a - b + \frac {b}{\cos \left (f x + e\right )^{2}}} \cos \left (f x + e\right )}}{3 \, f} \]
[In]
[Out]
\[ \int \frac {\sin ^3(e+f x)}{\left (a+b \tan ^2(e+f x)\right )^{3/2}} \, dx=\int { \frac {\sin \left (f x + e\right )^{3}}{{\left (b \tan \left (f x + e\right )^{2} + a\right )}^{\frac {3}{2}}} \,d x } \]
[In]
[Out]
Timed out. \[ \int \frac {\sin ^3(e+f x)}{\left (a+b \tan ^2(e+f x)\right )^{3/2}} \, dx=\int \frac {{\sin \left (e+f\,x\right )}^3}{{\left (b\,{\mathrm {tan}\left (e+f\,x\right )}^2+a\right )}^{3/2}} \,d x \]
[In]
[Out]